下面代码的输出结果是:( )。1s= "F, 'f"]Def fun (a) :1s.append(a)ReturnFun ( "c " )Print ( 1s ) 选项: A: ['F', 'f''] B: ['C '] C: 出错 D:['F', 'f', 'C'] 结果是 出错 发布时间:2024-05-09 15:45:29