下面代码的输出结果是( )。Ls = "F","f"]Def fun ( a) :Ls. append(a)ReturnFun ( "C")Print(ls) 选项: A:'F',' f] B:'C'] C:出错 D:'F','F,' C'] 结果是 出错 发布时间:2024-05-09 15:32:23