下面代码的输出结果是()。Is = "F", "f"]Def fun (a) : Is.append (a) returnFun ( "C" )Print (1s ) 选项: A:'F', 'f '] B:'C'] C:出错 D:'F','f ','C'] 结果是 出错 发布时间:2024-05-09 15:32:23