若光子的波长和电子的德布罗意波长`\lambda`相等,试求光子的质量与电子的质量之
比.`m_{0}`为电子的静止质量.
选项:
A:`\frac{1}{\sqrt{1+m_{0}^{2}c^{2}}`
B:`\frac{1}{\sqrt{1-m_{0}^{2}c^{2}}`
C:`\frac{1}{\sqrt{1-(m_{0}^{2}\lambda^{2}c^{2}/h^{2})}`
D:`\frac{1}{\sqrt{1+(m_{0}^{2}\lambda^{2}c^{2}/h^{2})}`
E:`\sqrt{1+(m_{0}^{2}\lambda^{2}c^{2}/h^{2})}`
F:`\sqrt{1-(m_{0}^{2}\lambda^{2}c^{2}/h^{2})}`
发布时间:2024-04-11 19:51:23