请说出E类中【代码1】，【代码2】的输出结果。（请注意不同数据类型的输出表示） class A { double f(double x,do

1. 请说出E类中【代码1】，【代码2】的输出结果。class A { double f(double x,double y) { return x+y; }}class B extends A { double f(int x,int y) { return x*y; }}public class E {public static void main(String args[]) { B b=new B(); System.out.println(b.f(3,5)); //【代码1】 System.out.println(b.f(3.0,5.0)); //【代码2】 }}

2.中国大学MOOC: 请说出E类中【代码1】的输出结果。class A { double f(double x,double y) { return x+y; }}class B extends A { double f(int x,int y) { return x*y; }}public class E {public static void main(String args[]) { B b=new B(); System.out.println(b.f(3,5)); //【代码1】

3.E类中【代码1】,【代码2】的输出结果分别是_______,_________。 class A { double f(int x,double y) { return x+y; } int f(int x,int y) { return x*y; } } public class E { public static void main(String args[]) { A a=new A(); System.out.println(a.f(10,10)); //【代码1】 System.out.println(a.f(10,10.0)); //【代码2】 } }

4.请说出E类中【代码1】和【代码2】的输出结果。 class A { double f(int x,double y) { return x+y; } int f(int x,int y) { return x*y; } } public class E { public static void main(String args[]) { A a=new A(); System.out.println(a.f(10,10)); //【代码1】 System.out.println(a.f(10,10.0)); //【代码2】 } }

5.请说出下面程序中【代码1】和【代码2】的输出结果。 Plain Textinterface A { double f(double x,double y); } class B implements A { public double f(double x,double y) { return x*y; } int g(int a,int b) { return a+b; } } public class Main { public static void main(String args[]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 } }

6.请说出E类中【代码1】，【代码2】的输出结果。interface A { double f(double x,double y);}class B implements A { public double f(double x,double y) { return x*y; } int g(int a,int b) { return a+b; }}public class E {public static void main(String args[]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 }}

7.请说出E类中【代码1】，【代码2】的输出结果。interface A { double f(double x,double y); }class B implements A { public double f(double x,double y) { return x*y; } int g(int a,int b) { return a+b; }}public class E {public static void main(String args[]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 }}

8.请选出E类中System.out.println的输出结果 class A{ double f(double x,double y){ return x+y; } } class B extends A{ double f(int x,int y){ return x*y; } } public class E { public static void main(String[] args) { B b=new B(); System.out.println(b.f(3, 5)); System.out.println(b.f(3.0,5.0)); } }

9.请说出E类中【代码1】，【代码2】的输出结果____。（两个结果之间用英文状态下的#隔开）interface A { double f(double x,double y); }class B implements A { public double f(double x,double y) { return x*y; } int g(int a,int b) { return a+b; }}public class E {public static void main(String args[]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 }}

10.输出运行结果。Class A { double f(int x,double y) { return x+y; } int f(int x,int y) { return x*y; }}Public class E { public static void main(String args]) { A a=new A(); System.out.println(a.f(10,10)); //【代码1】 System.out.println(a.f(10,10.0)); //【代码2】 }}【代码1】____、【代码2】____。

11.请说出E类中[代码1]和[代码2]的输出结果。 class A{ double f(int x, double y){ return x y; } int f(int x,int y) { return x*y; } } public class E{ public static void main(String args[ ] ){ A a=new A(); System.out.println(a.f(10,10)) ; // [代码1] System.out.println(a.f (10,10.0)) ; // [代码2] } }

12.interface A {double f(double x, double y);}class B implements A {public double f(double x, double y) { return x * y;}int g(int a, int b) { return a + b;}}public class Main {public static void main(String args]) { A a = new B();System.out.println(a.f(3, 5)); //【代码1】B b = (B) a;System.out.println(b.g(3, 5)); //【代码2】}}00interface A {double f(double x, double y);}class B implements A {public double f(double x, double y) { return x * y;}int g(int a, int b) { return a + b;}}public class Main {public static void main(String args]) { A a = new B();System.out.println(a.f(3, 5)); //【代码1】B b = (B) a;System.out.println(b.g(3, 5)); //【代码2】}} 请说出下面程序中【代码1】和【代码2】的输出结果，以空格隔开。

13.interface A { double f(double x,double y); } class B implements A { public double f(double x,double y) { return x*y; } int g(int a,int b) { return a+b; } } public class E { public static void main(String args[]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 } }

14.请说出E类中【代码1】，【代码2】的输出结果。interface A { double f(double x,double y); }class B implements A { public double f(double x,double y) { return x*y; } int g(int a,int b) { return a+b; }}public class E {public static void main(String args[]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 }} 选项：A、15.0 B、8 C、16.0 D、7

15.请说出下面程序中【代码1】和【代码2】的输出结果，以空格隔开。Interface A { double f(double x,double y); }Class B implements A { public double f(double x,double y) { return x*y; } int g(intA,int b) { return a+b; }}Public class Main {Public static void main(String args]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 }}

16.请说出 E类中【代码 1】和【代码 2】的输出结果。interface A {double f(double x, double y);}class B implements A {publ ic double f(double x, double y){return x* y;}int gl int a, int b){return a t b;}}public class E {public static void main(String args[]){A a = new B()；System.out. println(a.f(3,5)); //【代码 1】B b=（B）a；System.out. println(b.g(3,5)); //【代码 2】 }}

17.请说出下面程序中【代码1】和【代码2】的输出结果，以空格隔开。 interface A { double f(double x, double y); } class B implements A { public double f(double x, double y) { return x * y; } int g(int a, int b) { return a + b; } } public class Main { public static void main(String args]) { A a = new B(); System.out.println(a.f(3, 5)); //【代码1】 B b = (B) a; System.out.println(b.g(3, 5)); //【代码2】 } }

18.请写出类E的执行结果。class A{ double f(double x，double y){ return x*y;}}class B extends A{ double f(int x,int y){ return x+y； }}public class E{ public static void main（String args[]){ B b = new B()； System.out.println(b.f(5.0，15.0)); }}

19.请写出类E的执行结果。class A{ double f(double x，double y){ return x*y;}}class B extends A{ double f(int x,int y){ return x+y； }}public class E{ public static void main（String args[]){ B b = new B()； System.out.println(b.f(5.0，15.0)); }}

20.class A{ double f(double x,double y){ return x+y; }}class B extends A{ double f(int x,int y) { return x*y; }}public class E{ public static void main(String args[]) { B b=new B(); System.out.println(b.f(8.0,12.0)); }}运行结果是

21.说出下列E类中【代码1】~【代码2】的输出结果。（输入的答案要求两个数值间用逗号隔开）class A { double f(int x,double y) { return x+y; } int f(int x,int y) { return x%y; }}public class E { public static void main(String args[]) { A a=new A(); System.out.println(a.f(10,3)); //【代码1】 System.out.println(a.f(10,10.0)); //【代码2】 }}

22.(单选题, 2分)请说出E类的输出结果。Interface A { double f(double x,double y); }class B implements A { public double f(double x,double y) { return x*y; } int g(intA,int b) { return a+b; }}public class E {public static void main(String args]) { A a = new B(); System.out.println(a.f(3,5)); //【代码1】 B b = (B)a; System.out.println(b.g(3,5)); //【代码2】 }} 选项： A: 15.08.0 B: 158 C: 15.08 D: 158.0