It isn't the first time that I___ myself in an embarrassing situation
选项:
A:
Have found
B:
Found
C:
Find
D:
Was found
Have found
Found
Find
Was found
以下文字与答案无关
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one will find
B:can one find
C:one has found
D:to have been found
will find
B:find
C:found
D:are finding
find
B:found
C:to find
D:finding
Find
B:Finding
C:To find
D:Found
found
B:was founded
C:is founded
D:was found
A、Lost and found office
B、Baggage claim area
C、Customs
D、Airplane
change
B:model
C:progress
D:renewal
made out
B:found out
C:through out
D:thought out
indulge
B:induce
C:intrude
D:incorporate
A、in damaged condition
B、in damaged situation
C、severely damaged
D、damaged severely
argue
B:begin
C:meet
D:compete
who
B:whose
C:where
D:which
found out
C:through out
D:thought out
">14.I have ________ what he likes to eat and wear. 选项: A:made out
B:found out
C:through out
D:thought out
for(i=0;i<10;i++)
/************found************/
if(___(1)___)
{ f=1;
/************found************/
___(2)___;
}
if(f)
printf("%d is No. %d\n", n,k);
else
printf(" %d not found !\n",n);
}
">15.2.查找n在数组a中最后一次出现的位置(数组首元素的位置为零)。例如:如果a数组中的元素为:1,5,2,5,6,8,7,4,3,0,
当n=5时,程序的输出结果为:5 is No.3 。
当n=10时,程序的输出结果应为:10 not found !。
#include <stdio.h>
void main( )
{ int a10]={1,5,2,5,6,8,7,4,3,0};
int i,k,n,f=0;
scanf("%d",&n);
for(i=0;i<10;i++)
/************found************/
if(___(1)___)
{ f=1;
/************found************/
___(2)___;
}
if(f)
printf("%d is No. %d\n", n,k);
else
printf(" %d not found !\n",n);
}
is taken
B:takes
C:will be taken
D:has been found
A、accept,put
B、acceptable, place
C、accept, allow
D、acceptable, admit
- _________
选项: A:I found one novel.
B:No, novels cannot read
C:Novels are bad.
D:Yes. I like reading novels.
mutter
B:temporal
C:consecutive
D:composite