以下文字与答案无关
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a="1,'a', 2, 'b']"
B:a = {1,'a', 2, 'b']}
C:a = 1,'a', 2, 'b']]
D:a=(1,'a', 2, 'b'])
{k:1,k1:2,k2:3,k3:4}
C:'k':'1',、'k1':'2', 'k2':'3','k3':'4']
D:{'k':'1', 'k1': '2', 'k2': '3', 'k3': '4'}
">3.下面代码的输出结果是()。 str1="k:1|k1:2|k2:3|k3:4" str_list=str1.split('|') d={} for l in str_list: key,value=l.split(':') dkey]=value print(d) 选项: A:k:1,k1:2,k2:3,k3:4]
B:{k:1,k1:2,k2:3,k3:4}
C:'k':'1',、'k1':'2', 'k2':'3','k3':'4']
D:{'k':'1', 'k1': '2', 'k2': '3', 'k3': '4'}
import numpy as np
import matplotlib.pyplot as plt
data = np.array(20, 50, 10, 15, 30, 55])
pie_labels = np.array('A', 'B', 'C', 'D', 'E', 'F'])
plt.pie(data, labels=pie_labels)
plt.show()
B:import numpy as np
import matplotlib.pyplot as plt
data = np.array(20, 50, 10, 15, 30, 55])
pie_labels = np.array('A', 'B', 'C', 'D', 'E', 'F'])
plt.pie(data, radius=1.5, labels=pie_labels)
plt.show()
C:import numpy as np
import matplotlib.pyplot as plt
data = np.array(20, 50, 10, 15, 30, 55])
pie_labels = np.array('A', 'B', 'C', 'D', 'E', 'F'])
plt.pie(data, radius=1.5, explode=0, 0.2, 0, 0, 0, 0],labels=pie_labels)
plt.show()
D:import numpy as np
import matplotlib.pyplot as plt
data = np.array(20, 50, 10, 15, 30, 55])
pie_labels = np.array('A', 'B', 'C', 'D', 'E', 'F'])
plt.pie(data, radius=1.5, wedgeprops={'width': 0.6},labels=pie_labels)
plt.show()
Str_list=str1.split('|')
D={}
For l in str_list:
key,value=l.split(':')
Dkey]=value
Print(d)
选项: A:k:1,k1:2,k2:3,k3:4]
B:{k:1,k1:2,k2:3,k3:4}
C:'k':'1,'k1':2'','k2':'3','k3':'4']
D:{'k':'1,'k1':2'','k2':'3','k3':'4'}
">5.下面代码的输出结果是()。Str1="k:1|k1:2|k2:3|k3:4"
Str_list=str1.split('|')
D={}
For l in str_list:
key,value=l.split(':')
Dkey]=value
Print(d)
选项: A:k:1,k1:2,k2:3,k3:4]
B:{k:1,k1:2,k2:3,k3:4}
C:'k':'1,'k1':2'','k2':'3','k3':'4']
D:{'k':'1,'k1':2'','k2':'3','k3':'4'}
'2.5+1+2'
C:'5.5'
D:5.5
">7.表达式eval("5/2+5%2+5//2")的结果是( )。 选项: A:'2.5_1_2'
B:'2.5+1+2'
C:'5.5'
D:5.5
<class 'tuple'>
B:<class 'dict'>
C:<class 'set'>
D:<class 'list'>
1'-OH
B:3'-P
C:2'-OH
D:3'-OH
E:5'-P
def foo(arg1, arg2='test', arg3=100):
print arg1, arg2, arg3
选项: A:foo(arg1 = 'where', arg2 = 'what')
B:foo('where')
C:foo('where','what')
D:foo(arg = 'where')
def foo(arg1, arg2='test', arg3=100):
print (arg1, arg2, arg3)
选项: A:foo(arg1 = 'where', arg2 = 'what')
B:foo('where')
C:foo('where','what')
D:foo(arg = 'where')