求“能被3除尽,用5除余2,用8除余5,用11除余8,用14除余11”的正整数,该问题的解答的表达形式为:
选项:
A:9240k+9237,k=0,1,2,3,…;
B:9240k-3,k=1,2,3,…;
C:18480k+9237,k=0,1,2,3,…;
D:18480k-3,k=1,2,3,…;
E:18480k+18477,k=0,1,2,3,…;
F:18480k-9243,k=1,2,3,…; G:9240k+18477,k=0,1,2,3,…; H:18480k+10557,k=0,1,2,3,…
发布时间:2024-05-16 10:58:35