下列程序的输出结果为（ ）。#include void main(){ int i, j, min; int x = 0, y= 0; int a[3][3] = { {1, 2, 3}, {2, -3, 4},{7, 4, 7} }; min = a[0][0]; for (i = 0; i < 3; i++) { for (j = 0; j < 3; j++) { if (a[i][j] >= min) { min = a[i][j]; x = i+1; y = j+1; } } } printf("min=%d at (x,y):(%d,%d)\n", min, x, y);}
选项：

A:min=7 at (x,y):(3,3) ;
B:min=7 at (x,y):(3,1);
C:min=3 at (x,y):(1,3);
D:7 3 3